www.arves.org - Polish Chess Fed 2023

Studies awarded for the Polish Chess Federation 2023 tournament.

[Event "1/2.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Costeff=G"] [Black ""] [Result "1/2-1/2"] [SetUp "1"] [FEN "N2Rn1B1/Ppp1P2p/7P/6bp/2p5/1pP5/1Pp1PPkn/4K3 w - - 0 1"] [PlyCount "16"] [EventDate "2023"] 
 {The so-called 'checkers theme' realized in a paradoxical 'inverted' form. The usual way of implementing it is as follows: in the initial play White places the opponent's pieces on the appropriate fields, and then with a series of checks (usually with a knight) gains them. Here we have the following situation: White can threaten after the departure of the knight from a8 to promote a queen on this square, but Black has a series of moves defending the square a8. The white king is in a stalemate position at this point, but there is a free pawn on the e-line, a bishop on g8 and possibly a knight on the chessboard, making it "far from stalemate". Therefore, with a series of preparatory moves White sets the pawn, and the knight on respective squares and now the black manoeuvre in turn captures the three white pieces and stalemate becomes reality!} 1. Rd1 Nf1 2. Bd5+ $1 {The threat was 2... Bd2+, so White has to unblock the e2 square for his king. We can play with this purpose} (2. e4 $2 {but Black plays} cxd1=Q+ 3. Kxd1 Kxf2 4. Nb6 Ne3+ 5. Kc1 Nd5+ 6. Kd1 Nxb6 {and the a8 field is controlled. The white king is in a stalemate position, but after} 7. a8=Q Nxa8 {it's not a stalemate because of the Pe4 and Bg8. Therefore White carries out a manoeuvre: he places his three pieces in the path of the knight from f1 to b6. This positioning must be done in the correct order}) (2. e3 $2 cxd1=Q+ 3. Kxd1 Kxf2 4. Nb6 Nxe3+ 5. Kc1 Nd5+ 6. Kd1 Nxb6 7. a8=Q Nxa8 {no stalemate because of the Bg8.}) (2. Nb6 $2 { does not defend against the threat.}) 2... Kg1 3. e3 $1 {We already know that} (3. e4 $2 {is bad, because the pawn will stay on the chessboard and there will be no stalemate.}) (3. Nb6 $2 Bd2+ $1) 3... cxd1=Q+ 4. Kxd1 Kxf2 5. Nb6 $1 { Now Black is left with no choice but to carry out his march with the knight, but is forced to eliminate all the white pieces obstructing the stalemate along the way:} (5. Nxc7 $2 Nxe3+ 6. Kc1 Nxd5+ 7. Kd1 Nb6 $1 {and the knight will stay on the chessboard and there will be no stalemate.}) 5... Nxe3+ 6. Kc1 $1 (6. Kd2 $2 Kf1 7. a8=Q Ng4+ 8. Kd1 Nf2#) 6... Nxd5+ 7. Kd1 Nxb6 8. a8=Q Nxa8 {stalemate. This is an example of "checkers theme" in traditional form. Leonid Kubbel, Listok Szachmatnogo Kruzhka Petrogubkommuni 1921. Kb5, Qh7, Rh6, Nc4, Pb3 - Ka8, Qf8, Rd8, Bc7, Pa5; Win. 1. Qe4+ Kb8 2. Rb6=! Bxb6 3. Ka6 Rd7 4. Qa8+ Kxa8 5. Nxb6+ Kb8 6. Nxd7+ K~ 7. Nxf8 win.} 1/2-1/2

[Event "1/2.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Kwiatkowski=M"] [Black ""] [Result "1-0"] [SetUp "1"] [FEN "6bK/5pR1/2Bq2pQ/b6p/8/2N5/1p4P1/7k w - - 0 1"] [PlyCount "15"] [EventDate "2023"] 
 {An excellent and impressive study. First, the pawn's trip from the g2 field to the f7 square in the style of S.Loyd's famous task. When the pawn reaches the f7, it can complete the excelsior theme in two ways: to capture the black bishop on g8 or to play f8Q without capturing. In response, black also promotes to queen and there are four queens on the chessboard - possibly with an additional black bishop. It turns out that one has to choose the latter solution only to lose a tempo and capture the bishop by the promoted queen a move later obtaining an extraordinary position of mutual zugzwang with two queens against two queens. The idea of mutual zugzwang involving the queens is extremely difficult to implement, because mostly in positions with queens, whoever has the move has a decisive advantage. The author has managed to find an ingenious way for a queen to lose a tempo - namely, he loses this tempo in two steps: the first move "before her birth" - while still being a pawn, and in the second move already as a queen! This zugzwang position was already used by N.Elkies - FIDE Album 1992-94 D07 (no 90522 in Didukh base). But there the game is completely different and there is no thematic try leading to the key position with the white to move, so there is no mutual zugzwang theme in that study. Thus this study can be considered as fully original.} 1. g4+ $1 Qxc6 2. gxh5 $1 Bxc3 (2... f5 3. hxg6+ Kg1 4. Qg5+ Qg2 5. Ne2+ Kf2 6. Qxg2+ Kxg2 7. Rb7 Bc4 8. Rxb2 Bd8 9. Nd4+ (9. Kg7 Kf2 10. Nd4+ Ke3 11. Nxf5+ $18) 9... Kf1 10. g7 Bf6 11. Rb1+ Kf2 12. Nxf5 $18) (2... Qc7 3. hxg6+ Qh2 4. Qxh2+ Kxh2 5. Nb1 $18) 3. hxg6+ Kg1 4. gxf7+ Bxg7+ 5. Qxg7+ Kh1 $1 (5... Qg2 6. fxg8=Q $18 (6. f8=Q $2 b1=Q 7. Qc5+ Kh1 $11)) 6. f8=Q $3 (6. fxg8=Q $2 b1=Q {mutual zugzwang position with WTM. White must take control off the h6 field, either from the eighth line or the a1-g7 diagonal allowing the check.}) 6... b1=Q 7. Qfxg8 {mutual zugzwang position with BTM. Now black have to take control from one of the fields: g1, g2, h7, h6 and they get a quick mate. For example:} Qbc1 (7... Qce4 8. Qh6+) 8. Q8h7+ {Here is the montioned famous Loyd's problem: Samuel Loyd, Era 1861, Kh5, Rb5, Re2, Na1, Nh3, Pb2, c2, g3 - Kh1, Rc8, Bd8, Na8, Pa3, b6, b7, e3, f7, h7; #5.1.b4 Rc5+ 2, bc5 a2 3.c6 Bc7 4.cb7 ~ 5.ba8Q(B)#.} 1-0

[Event "3/4.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Gigola=J Piliczewski=B Borisenko=I"] [Black ""] [Result "1-0"] [SetUp "1"] [FEN "8/3p4/8/8/p2K4/8/k3b1N1/N1B5 w - - 0 1"] [PlyCount "37"] [EventDate "2023"] 
 1. Nf4 Bg4 ({main B} 1... Bd1 2. Nd5 Kxa1 (2... Kb1 {(C)} 3. Ba3 Kxa1 (3... Ka2 4. Bb4 Kxa1 5. Nc3 Bf3 6. Ba3 d5 7. Kd3 Be4+ 8. Kd2 d4 9. Nxe4 $18) 4. Nc3 Bb3 (4... Bc2 5. Kc5 {or} (5. Kd5) 5... Bb3 6. Kd6 {etc. as in A}) 5. Ke3 $1 (5. Kd3 $2 d5 $1) 5... d5 6. Kd3 $1 {etc. as in B}) 3. Nc3 Bb3 4. Ba3 $1 {Thematic try:} (4. Kd3 $2 d6 $1 5. Ba3 d5 $1 {and a second key position arose this time of mutual zugzwang with White to move:} 6. Kd2 {Kc2} (6. Kd4) 6... d4 {and the bishop blocks the c1 field to the king. It is necessary for black to move the pawn first and depending on this white will decide whether to lose the tempo or not!}) 4... d6 $1 {4... d6 a loss of tempo, but white can respond with the same!} (4... d5 {black doesn't lose the tempo, then so do we!} 5. Kd3 $1) 5. Ke3 $1 (5. Kd3 $2 d5 $1) (5. Ke4 $2 Bc4 $1 $11) 5... d5 6. Kd3 $1 {Mutual zugzwang position with BTM} Bc4+ 7. Kc2 Bb3+ 8. Kc1 d4 9. Bb2#) 2. Nd5 Be6 3. Nc3+ Kxa1 4. Ke5 $1 (4. Ba3 $2 d5 $1 5. Kd3 Bf5+ $11) 4... Bf7 5. Kd6 $1 (5. Ba3 $2 d5 $1 $11) 5... Be6 {We have one of the key positions of the study. White's main plan is to go with the king on a3 and mate with the bishop on b2. An attempt at 6. Kc5? fails because of 6.... d5 7. Kb4 d4 and white lacks one tempo to a mate. If there had been a move by black in this position, winning - as we will see in the 10th move - would have already been easier. It is therefore necessary to lose the tempo. This can only be done by the king with the triangle manoeuvre. But for the moment this is impossible, because all the white fields near the white king are under the control of the black pieces. Therefore white with a preliminary manoeuvre forces black to remove control from the d5 square.} 6. Ba3 $1 (6. Kc5 $2 d5 $1 7. Kb4 d4 $11) 6... Bf5 { The d7 pawn must be defended. Now the triangle manoeuvre comes through.} 7. Kd5 $1 (7. Bc1 Be6 8. Kc5 $2 d5 $1 $11) 7... Be6+ 8. Ke5 $1 Bf7 9. Kd6 $1 Be6 10. Bc1 $1 {The first task is done: in the key position the move has black. They have to give up the pawn a.} a3 $1 (10... Bf5 11. Kc5 $1 Be6 12. Kb4 d5 13. Ka3 d4 14. Bb2#) 11. Bxa3 Bf5 {12. Gc1 is still premature, because after 12... Ge6 a key position already without the pawn a, but still to carry out the main plan there needs to be a black move in this position. Therefore the second triangle manoeuvre.} 12. Kd5 $1 Be6+ 13. Ke5 $1 Bf7 14. Kd6 Be6 15. Bc1 $1 { it is already BTM.} Bf5 16. Kc5 Be6 (16... d5 17. Kxd5 $18) 17. Kb4 d5 18. Ka3 d4 19. Bb2# 1-0

[Event "3/4.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Pasman=M"] [Black ""] [Result "1/2-1/2"] [SetUp "1"] [FEN "7K/4Pk2/1p1R4/7P/5P2/7p/2b1P3/7n w - - 0 1"] [PlyCount "35"] [EventDate "2023"] 
 {The initial play is about stopping the h-pawn.} 1. Rc6 $1 (1. Re6 $2 Ba4 2. Re4 (2. Re3 Nf2) 2... Bc6 $1 $18) (1. Rd2 $2 Be4 $1 2. e3 Ng3 3. Rh2 Bg2 $18) 1... Ba4 2. Rc4 $1 (2. Rc3 $2 Nf2 $19) 2... Bb5 (2... Bd7 3. f5 Nf2 4. Rh4 { etc.}) 3. Rb4 Bd7 (3... Be8 4. f5 Nf2 5. Rh4 b5 6. h6 b4 7. Rxb4 h2 8. Rh4 h1=Q 9. Rxh1 Nxh1 10. e4 $1 $11) 4. f5 Nf2 5. Rh4 b5 {A key position has arisen. In order to draw you have to anticipate several moves ahead the position of mutual zugzwang and the necessity to lose tempo. Tempo can only be lost with the e pawn by moving it to the e4 field in two steps. It seems better to move first with the h-pawn 6.h6? and to be able to choose the right moment to lose the tempo. But it turns out that this moment is right now!} 6. e3 $3 (6. h6 $2 b4 7. Rxb4 h2 8. Rh4 h1=Q 9. Rxh1 Nxh1 10. e4 {the opportunity to lose the tempo has been irretrievably lost:} (10. e3 Nf2 $1 11. e4 Ng4 $19) 10... Ng3 $1 {we have the key original position of mutual zugzwang with WTM:} 11. f6 (11. h7 Nh5 12. e5 Bxf5 $19) 11... Nh5 12. e5 Bf5 $19) 6... b4 7. Rxb4 h2 8. Rh4 h1=Q 9. Rxh1 Nxh1 10. e4 $1 Ng3 (10... Nf2 {As the pawn is already on e4 it gives Black nothing:} 11. e5 Bxf5 12. e8=Q+ Kxe8 {forcing a stalemate or advancing the h-pawn.} 13. Kg7) 11. h6 $1 {The key position of mutual zugzwang with BTM.} (11. e5 $2 Nxf5 $19) 11... Nxe4 12. h7 Ng5 13. f6 Kxf6 14. Kg8 Be6+ 15. Kf8 Nxh7+ 16. Ke8 Ng5 17. Kf8 Bc4 18. e8=N+ $1 $11 1/2-1/2

[Event "5.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Babiarz=A"] [Black ""] [Result "1-0"] [SetUp "1"] [FEN "1R6/4p1K1/5p2/8/8/p7/8/k7 w - - 0 1"] [PlyCount "21"] [EventDate "2023"] 
 {If there were no black pawns on f6 and e7, then there would be an obvious draw, because in order to stop the a-pawn from promoting, White would have to stalemate Black. So, the white king comes to the black king in such a way as to leave at least one black pawn on the f- or e-line. It turns out that in the main variation you have to leave exactly one!} 1. Kg6 $1 (1. Kf7 $2 {is bad:} f5 2. Ke6 f4 3. Kd5 f3 4. Kc4 a2 5. Kb3 Kb1 6. Rd8 a1=N+ $1 $11 (6... Kc1 7. Kxa2 e5 8. Kb3 e4 9. Kc3 e3 10. Ra8 Kd1 11. Kd3 $18) 7. Kc3 {and a draw because there are two black pawns on the chessboard, black draws by playing e. g.} e5) 1... e6 $1 {Other moves will be followed by 2. Kf5 with an easy win in many ways. Now the f5-square is inaccessible for the white king because of the e6 pawn, but it will be possible to eliminate this pawn.} 2. Kf7 $1 ({After} 2. Kxf6 $2 e5 {you have to capture the the second pawn or lose a valuable tempo and the e-pawn escapes.}) 2... f5 {Now we perform the same manoeuvre as in the try, but on the way we capture the e-pawn, leaving the f-pawn.} (2... a2 3. Kxe6 f5 4. Kd5 f4 5. Kc4) 3. Kxe6 f4 4. Kd5 f3 5. Kc4 a2 6. Kb3 Kb1 7. Rd8 a1=N+ 8. Kc3 {There is only one pawn on the chessboard and White wins.} Kc1 9. Rd2 {and if there had been aditionally pawn on e7, it would have drawn 9...e5/ e6.} Nb3 10. Rf2 Kd1 11. Kxb3 $18 (11. Rxf3 $2 Ke2 $11) 1-0

[Event "sp.p Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Piliczewski=B"] [Black ""] [Result "1/2-1/2"] [SetUp "1"] [FEN "8/8/2b5/8/8/8/2k2r2/K5R1 w - - 0 1"] [PlyCount "22"] [EventDate "2023"] 
 {A theoretical position containing surprisingly rich artistic content: a logical try, four stalemates appearing at different phases of the game, a 'switchback'. Admittedly, the stalemates are not model and very attractive, but what is noteworthy is their number and their variety. Certainly individually these stalemates have appeared before, e.g. stalemates 2 and 3: S. Gawlikowski, Endgame chess, Koсcowa gra szachowa, Zakoсczenia figurowo pionowe, 1954, position 1064 . But the collection of all these stalemates in one study is probably a novelty. The study is of theoretical value - it explains the subtle differences between winning and draw positions in endings RB v R.} 1. Rc1+ $1 {The king has to be chased away to field a3, and this has to be done as long as the black rook is on the f2.} (1. Ka2 $2 Rf4 2. Rg3 Ra4+ 3. Ra3 Bd5+ 4. Ka1 Rxa3#) (1. Re1 $2 Rd2 $1 2. Re5 (2. Ka2 Bb5 $1 3. Rb1 (3. Ka3 Rd4 $19) 3... Bc4+ 4. Ka1 Kc3 5. Rb2 Rd1+ 6. Rb1 Rd3 7. Rc1+ Kb3 8. Rb1+ Ka3 $19) ({if we now try to play analogously to the main game} 2. Rc1+ {then} Kb3 3. Rb1+ Ka3 4. Re1 Be4 5. Re3+ Bd3 {here's the difference: the bishop can take cover on d3.}) 2... Rd3 3. Re2+ Kc1 4. Re1+ Kd2 5. Rb1 Kc3 6. Rc1+ Kb3 7. Rb1+ Ka3 $19) 1... Kb3 (1... Kxc1 {stalemate-1.}) 2. Rb1+ $1 (2. Rxc6 $2 Rf1+ 3. Rc1 Rxc1#) ({The logical try} 2. Re1 $2 {is still premature. Black has two routes to victory, both exploiting the possibility of the black king going to c2:} Rf3 {also} (2... Rd2 3. Re3+ Kc2 4. Re5 $19) 3. Kb1 Ba4 4. Ka1 (4. Kc1 Kc3 $19) 4... Kc2 5. Re2+ Kc1 {. Both these ways to win will be ineffective with the black king on a3.}) 2... Ka3 3. Re1 $1 {Only now. The white rook controls the important field e4 and now after 3.... Be4 4. Re3+ easily draws.} (3. Rg1 $2 Ra2+ 4. Kb1 Be4+ 5. Kc1 Ra1+ 6. Kd2 Rxg1 $19) (3. Rd1 $2 Ra2+ 4. Kb1 Be4+ 5. Kc1 Rc2+ 6. Kb1 Kb3 7. Re1 Rc4+ 8. Ka1 Ra4#) (3. Rb2 $2 {Allows black to move the bishop to b3 and then to c4, and the king to c3 with a win: This is a winning method already known in the 19th century.}) 3... Rf3 ( 3... Bd5 4. Kb1 Bb3 5. Kc1 $11) 4. Kb1 Rc3 $1 (4... Kb3 5. Kc1 Kc3 6. Kd1 $11) 5. Re5 $1 {Does not allow the knight to enter field b5} (5. Re6 $2 Bb5 6. Re1 Bd3+ 7. Ka1 Rc2 $19) (5. Re7 $2 Bg2 6. Ra7+ Kb3 7. Re7 Bd5 8. Re8 Ka3 9. Re2 Bc4 $19) 5... Kb3 {It seems that white is in a zugzwang and must lose control of the b5 or e4 field, but it turns out that they have the only defence:} 6. Re2 $1 (6. Re6 $2 Bb5 $1 7. Rb6 Rc5 $1 8. Rb8 Kc3 9. Kc1 Rf5 10. Rc8+ Bc4 $19) 6... Bd5 {"Catching" the a2 field from behind the king.} (6... Bb5 7. Rb2+ $11) 7. Rb2+ (7. Re7 $2 Rd3 8. Kc1 Bf3 $1 9. Re1 Bg4 10. Rg1 Be2 11. Re1 Bf3 12. Rf1 Kc3 13. Kb1 Be4 $19) 7... Ka3 8. Ka1 $1 {It is not possible to 8. Ra2+?, but it is possible to seemingly deteriorate of the king's position by playing to the corner! It is worth looking at this position to understand at least part of the theoretical value of the study. If the black rook had stood on another field on the 3rd line instead of on c3, it would have won 8.... Bb3 9. Ra2+ Kb4 10. Rf2 Kc3! And now the rook blocks the c3 aquare and therefore white draws.} (8. Re2 $2 Bc4 $19) 8... Rf3 {Black unblocks the c3 square, but fortunately for white it is too late.} (8... Rc1+ 9. Rb1 Rc2 10. Rb2 $1 Rxb2 { stalemate-2.}) 9. Ra2+ $1 (9. Rb1 $2 Re3 10. Rc1 Bc6 11. Rb1 Re5 12. Rb2 Ba4 $19) 9... Kb3 (9... Bxa2 {stalemate-3.}) 10. Rb2+ Kc3 11. Rc2+ $1 Kxc2 {stalemate-4.]} 1/2-1/2

[Event ".hm Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Tkachenko=SN"] [Black ""] [Result "1/2-1/2"] [SetUp "1"] [FEN "8/P7/3P1N2/1B6/1r6/3Kp3/R2P2p1/5rkb b - - 0 1"] [PlyCount "21"] [EventDate "2023"] 
 1... e2 $1 (1... Rb3+ 2. Kc4 Rfb1 3. dxe3 Kf1 4. Rxg2 Bxg2 5. d7 $11) 2. Kxe2 Re1+ $3 (2... Rf2+ 3. Kd3 (3. Ke3 Rb3+ 4. Bd3 Rxf6 5. a8=Q Re6+ 6. Kd4 Rxd6+ 7. Kc4 Rbxd3 $11) 3... Kh2 4. Ra1 g1=Q 5. Rxg1 Kxg1 6. d7 Rb2 7. Kc3 Rbxd2 8. Bd3 Rxd3+ 9. Kxd3 Rf3+ 10. Kc2 Rf2+ 11. Kd1 Rf1+ 12. Ke2 Rf2+ 13. Ke3 Rf3+ $11) ( 2... Kh2 $2 3. a8=Q Re1+ (3... g1=Q 4. Qh8+ Kg3 5. Qg7+ Kh2 6. Qh6+ Kg3 7. Nh5+ Kg4 8. Bd7+ Rf5 9. Bxf5+ Kxf5 10. Ra5+) 4. Kd3 $1 Rd4+ 5. Kc3 Rc1+ 6. Rc2 Rxc2+ 7. Kxc2 g1=Q 8. Qh8+ Kg2 9. Bc6+ Kf1 10. Qh3+ Ke1 11. Qe6+ Kf1 12. Qf5+ Qf2 13. Qxf2+ Kxf2 14. Bxh1 $18) 3. Kxe1 Kh2 $1 4. Ng4+ $1 (4. a8=Q $2 g1=Q+ 5. Ke2 Bxa8 6. Rxa8 Qg2+ $19) 4... Rxg4 5. d4 $1 (5. d3 $2 Kg3 $1 6. Rxg2+ Bxg2 7. Kd2 Rd4 8. d7 Kf4 9. Kc3 Ke5) 5... Kg3 $1 (5... Re4+ 6. Kd2 g1=Q 7. a8=Q Qxd4+ ( 7... Re2+ 8. Bxe2 Bxa8 9. Rxa8 Qxd4+ 10. Bd3 $1 $11) 8. Kc1+ Bg2 9. Rxg2+ Kxg2 10. d7 $11) 6. Rxg2+ Bxg2 7. d5 $1 Bxd5 8. d7 Rg8 9. Bc4 $3 Bxc4 10. a8=Q $1 Rxa8 11. d8=Q Rxd8 {stalemate.} 1/2-1/2

[Event ".c Polish ty"] [Site ""] [Date "2023"] [Round ""] [White "Avni=A"] [Black ""] [Result "1/2-1/2"] [SetUp "1"] [FEN "2n2k2/8/2KP3q/8/8/1p2N3/5B2/5R2 w - - 0 1"] [PlyCount "23"] [EventDate "2023"] 
 1. Nf5 (1. Bg3+ $2 Ke8 2. Nf5 Na7+ 3. Kc5 Qf6 $19) (1. Nc4 $2 Qf6 2. Bc5 (2. Kc5 Qf5+ 3. Kb4 Nxd6 4. Nxd6 Qd3 5. Rg1 b2 $19) 2... Qxf1 3. d7+ Ne7+ $19) 1... Qg6 (1... Qe6 2. Bc5 Kg8 3. Rf2 $1 Qe4+ (3... b2 4. Rg2+ Kf7 5. Rxb2 Qe4+ 6. Kc7 $11) 4. Kc7 Qc4 5. d7 Qxc5+ 6. Kb8 $11) 2. Bc5 (2. Bg3 $2 Na7+ 3. Kb6 (3. Kc7 Qf7+ 4. d7 Qc4+ 5. Kb7 Qc6+ 6. Kxa7 Qxd7+ $19) (3. Kc5 Ke8 4. Be5 Kd7 (4... Kd8 5. Ne3 Qe8 6. Kd5 Nc6 7. Nc4 Nxe5 8. Nxe5 Qb5+ 9. Ke6 Qxf1 $19) 5. Ne3 b2 6. Bxb2 Qxd6+ $19) 3... Qf7 4. Ne3 b2 5. d7 b1=Q+ 6. Rxb1 Qxd7 $19) (2. Kc7 $2 Nxd6 3. Bc5 b2 4. Bxd6+ Ke8 $19) 2... Ke8 (2... Na7+ 3. Kc7 Nb5+ 4. Kc6 Qg2+ 5. Kb6 Qxf1 6. d7+ Kf7 7. d8=Q Qxf5 8. Qf8+ Ke6 9. Qc8+ $11) 3. Ng7+ $1 (3. Kc7 $2 Qh7+ 4. Ne7 Nxd6 5. Bxd6 b2 $19) 3... Qxg7 4. Rf8+ $3 Qxf8 (4... Kxf8 5. d7+ Ne7+ 6. Kb5 $1 $11) 5. d7+ Kd8 6. Bxf8 (6. dxc8=Q+ $2 Kxc8 7. Bxf8 b2 $19) 6... b2 7. Bb4 $1 Na7+ 8. Kd6 Nc8+ 9. Kc6 (9. Ke6 $2 b1=Q 10. Ba5+ Nb6 $19) 9... Na7+ 10. Kd6 Nb5+ 11. Kc6 (11. Ke6 $2 Nc7+ 12. Kd6 b1=Q $19) 11... Nd4+ 12. Kd6 $11 1/2-1/2